Programming Challenges Question 7

Programming Challenges Question 
Write a program that accepts 10 student records (roll number and score) and prints them in decreasing order of scores. In case there are multiple records pertaining to the same student, the program should choose a single record containing the highest score. The program should be capable of accepting a multi-line input. Each subsequent line of input will contain a student record, that is, a roll number and a score (separated by a hyphen). The output should consist of the combination of roll number and corresponding score in decreasing order of score.

INPUT to program

1001-40
1002-50
1003-60
1002-80
1005-35
1005-55
1007-68
1009-99
1009-10
1004-89

OUTPUT from program

1009-99
1004-89
1002-80
1007-68
1003-60
1005-55
1001-40

Solution

//******************************Code in JAVA*************************************//
import java.io.*;
import java.util.*;

public class Main {
    public static void main(String[] args) {
       String Data[]= new String[10];
       int splitData[][]= new int[10][2];

       InputStreamReader sr= new InputStreamReader(System.in);
       BufferedReader br= new BufferedReader(sr) ;
       try{
          for(int i=0;i<10;i++)
          {
           Data[i]=br.readLine();
           String str[]= Data[i].split("-");
           splitData[i][0]=Integer.parseInt(str[1]);
           splitData[i][1]=Integer.parseInt(str[0]);
          }

     Arrays.sort(splitData, new Comparator<int[]>() {
            public int compare(int[] o1, int[] o2) {
            return o2[0] - o1[0];
        }
    });

         Byte flag=0;  
          for(int i=0;i<10;i++)
          {
            flag=0;
            for(int j=i-1;j>=0;j--)
            {
                if(splitData[i][1]==splitData[j][1])
                {
                  flag=1;
                   break;
                }
            }
            if(flag==1)
                continue;
            else
                System.out.println(splitData[i][1]+"-"+splitData[i][0]);
}
      }
      catch(Exception ex)
      {
          System.out.println(ex.toString());
      }
     
      }

}